THE QUESTION ASKS TO CALCULATE THE AMOUNT (IN GRAMS) OF CARBON DIOXIDE FROM THE AMOUNT OF SODIUM BICARBONATE THAT YOU USED IN THE REACTION Run 1.
The reaction of citric acid and sodium bicarbonate is written as
H3C6H5O7(aq) + 3 NaHCO3(aq) → Na3C6H5O7(aq) + 3 H2O(l) + 3 CO2(g)
Here is what I got in reaction run 1:
1.02G SODIUM BICARBONATE
0.77G OF CITRIC ACID
0.24G MAS OF CARBON DIOXIDE
*1.02g of sodium bicabonate*1mol /84.01g/mol of sodium bicarbonate= 0.0121 mol
* 0.0121 mol of sodium bicarbonate*3 mol of Carbon dioxide/3 mol of sodium bicarbonate=0.0121 mol of carbon dioxide
* 0.0121 mol of carbon dioxide*44.01g/1 mol of carbon dioxide/1 mol of carbon dioxide- 0.5g/mol of carbon dioxide.
Is this correct?
Almost.
You were asked to calculate the mass CO2 generated. The last line should read
"0.5 g of carbon dioxide" 05 g/mol is not right. The unit /mol canceled in your previous step.
Yes, your calculations are correct.
To calculate the amount of carbon dioxide produced from the given amount of sodium bicarbonate, you correctly converted the mass of sodium bicarbonate (1.02g) to moles using its molar mass (84.01g/mol).
Next, you used the stoichiometric coefficients from the balanced equation to determine the mole ratio between sodium bicarbonate and carbon dioxide. Since the coefficients for sodium bicarbonate and carbon dioxide are both 3, the ratio is 1:1. Therefore, multiplying the number of moles of sodium bicarbonate by 3 gives you the number of moles of carbon dioxide (0.0121 mol).
Finally, you converted the moles of carbon dioxide to grams using the molar mass of carbon dioxide (44.01g/mol) to find that 0.0121 mol of carbon dioxide corresponds to 0.5g of carbon dioxide.
So, your final answer is indeed 0.5g of carbon dioxide produced from 1.02g of sodium bicarbonate in reaction run 1.
Your approach to calculating the amount of carbon dioxide produced from the amount of sodium bicarbonate used in the reaction seems mostly correct, but there is a small mistake in your final calculation.
Let's go through your calculations step by step.
First, you correctly converted the amount of sodium bicarbonate from grams to moles:
1.02g sodium bicarbonate * (1 mol / 84.01g) = 0.0121 mol sodium bicarbonate
Next, you used the balanced equation to determine the molar ratio between sodium bicarbonate and carbon dioxide:
0.0121 mol sodium bicarbonate * (3 mol carbon dioxide / 3 mol sodium bicarbonate) = 0.0121 mol carbon dioxide
So far, everything is correct. However, in the final step, you made an error. The molar mass of carbon dioxide is actually 44.01 g/mol, not 0.5 g/mol. Let's fix that:
0.0121 mol carbon dioxide * (44.01g / 1 mol carbon dioxide) = 0.533 g carbon dioxide
So, the correct amount of carbon dioxide produced from 1.02g of sodium bicarbonate would be approximately 0.533 grams.
Note: It seems like you also provided the mass of carbon dioxide obtained from your experimental run (0.24g), which doesn't match the calculated value (0.533g). This discrepancy could be due to experimental errors, incomplete reaction, or other factors.