Father gave Sue \frac{1}{8} of his money, gave Henry \frac{1}{2} of the remainder and kept the rest. Calculate the following:
a) The fraction that Henry got.
b) What fraction of the money was left? Answer
c) If father had $240.00 at the beginning, how much did father keep?
Remainder = 8/8 - 1/8 = 7/8.
a. 1/2 * 7/8 = 7/16 of the money.
b. 7/8 - 7/16 = 14/16 - 7/16 = 7/16 Remaining.
c. 7/16 * $240. =
To solve this problem, we'll break it down step by step.
a) The fraction that Henry got.
- Father gave Sue 1/8 of his money, so the remaining fraction is (1 - 1/8) = 7/8.
- Father then gave Henry 1/2 of this remaining money, so the fraction that Henry got is (1/2)*(7/8) = 7/16.
b) What fraction of the money was left?
- We already found that the fraction of money father kept was 7/8. So the fraction of money left is (1 - 7/8) = 1/8.
c) If father had $240.00 at the beginning, how much did father keep?
- We can set up a proportion using the fraction of money father kept:
(fraction of money kept) / (total money) = (amount of money kept) / (amount at the beginning)
7/8 = (amount of money kept) / $240.00
- Cross-multiplying, we get:
(amount of money kept) = (7/8) * $240.00 = $210.00
So, father kept $210.00.
To summarize:
a) The fraction that Henry got is 7/16.
b) The fraction of money that was left is 1/8.
c) If father had $240.00 at the beginning, he kept $210.00.