A man goes 30km due north and then 40km due east. how far away is he away from his initial position?
To find the distance the man is from his initial position, you can use the Pythagorean theorem. This theorem applies to right-angled triangles and states that the square of the hypotenuse is equal to the sum of the squares of the other two sides.
In this case, the man has travelled 30km due north and 40km due east, forming a right-angled triangle. The distance he is away from his initial position is the hypotenuse of this triangle.
Using the Pythagorean theorem, we can calculate the distance as follows:
1. Square the lengths of the two sides: (30km)^2 = 900km^2 and (40km)^2 = 1600km^2.
2. Add these two squares together: 900km^2 + 1600km^2 = 2500km^2.
3. Take the square root of the sum: √2500km^2.
Therefore, the man is |√2500km| = 50km away from his initial position.
Answers is wrong ok!!!
Not clear this answer
Pythagorean Theorem
30^2 + 40^2 = x^2
900 + 1600 = x^2
2500 = x^2
? = x