a bag contains 5 golden and 7 blue balls one ball is drawn it is found to be golden after noting the colour of the ball it is not put back in to the bag another ball is now drawn at random what is the probability that the second ball is drawn is golden
pr(secondgolden)=4/11....how did I get that?
Solve it
To find the probability that the second ball drawn is golden, we need to consider the first ball that was drawn. Since we know that the first ball drawn was golden and not put back into the bag, the number of golden balls in the bag has decreased by 1 and the total number of balls in the bag has decreased by 1.
Initially, there were 5 golden balls and 7 blue balls, making a total of 12 balls in the bag. After the first golden ball was drawn and not put back, there are now 4 golden balls and still 7 blue balls, making a total of 11 balls remaining in the bag.
The probability of drawing a golden ball as the second ball can be calculated by dividing the number of golden balls in the bag by the total number of balls in the bag.
Therefore, the probability of drawing a second golden ball is 4/11.