A ball is thrown upward with velocity 5m/s calculate total distance covered by it ?{
Using formulae (v)2 -(u)2. =2gs}
h(t) = 5t - 4.9t^2
max height at t=5/9.8
so, figure h at that value of t.
Total distance is that height up, then back down.
Using formulae (v)2 -(u)2. =2gs}
max height at t=5/9.8
so, figure h at that value of t.
Total distance is that height up, then back down.