Simplify
(5x+3)+(8x+1)
(5x)+(8x)= 13x^2
(5x)+(1)=5x
(3)+(8x)=11x
(3)+(1)=4
=13x^2+5x+11x+4
=13x^2+16x+4
Is this right or wrong?
Simplify
(2t^2-3t)-(7t^2-5t)
= (2t^2)-(7t^2)=-5t
= (2t^2)-(-5t)= 7t
=(-3t)-(7t^2)=-10t
=(-3t)-(-5t)=2t
=-5t+7t-10t+2t
I am confused. Why are all my answers "t" and none of them are "t^2"?
You do not show any multiplications or divisions in your given problems. All you can do is collect like terms.
(5x+3)+(8x+1)
is the same as
5x+3+8x+1
which is
13 x + 4
===========================
similarly
(2t^2-3t)-(7t^2-5t)
= 2 t^2 - 3 t - 7 t^2 + 5 t
Note that +5 t due to double - sign -( -5 ) = +5
= -5 t^2 + 2 t
Oh okay. So since there is a adding or subtracting sign with brackets, all you do is collect like terms? Okay. So it is not distributive property
no, not distributive property of multiplication
If the question were
(5x+3)(8x+1) no plus sign, so TIMES
then you could say
5x (8x+1)
+
3 (8x+1)
That would be distributive property.
In the first expression, the simplification seems to be incorrect.
Let's go through it step by step for better clarity:
(5x+3) + (8x+1)
To simplify it, we need to combine the like terms by adding the coefficients of x.
5x + 8x = 13x
3 + 1 = 4
So, the simplified expression is:
13x + 4
Now, let's move on to the second expression:
(2t^2-3t) - (7t^2-5t)
We can simplify it in a similar way:
2t^2 - 7t^2 = -5t^2
-3t - (-5t) = -3t + 5t = 2t
Note: The negative sign in front of (-5t) becomes positive when subtracting it.
Therefore, the simplified expression is:
-5t^2 + 2t
It seems like you're confused because you expected to see "t^2" in the final answer. However, in this case, the simplification led to an expression without a term involving "t^2". This can often happen during simplification when the given expression contains terms that can cancel each other out.
Don't worry, there isn't anything wrong with your work. Sometimes, simplification results in terms canceling out, which can lead to the absence of certain variables or exponents in the final expression.