this is a follow up question from my last one with the exact question
If you dissolve 200 g of salt in 20 l of water, what is the density of that solution of salty water? Hint: In this particular example, assume that the total volume doesn’t change when salt is added to water. You will need the mass of salt and the mass of water to find the mass of the solution of salty water. Don’t forget to show your working and include units.
http://www.jiskha.com/display.cgi?id=1488021668
To find the density of the solution of salty water, we need to determine the mass of the solution and the volume of the solution.
Let's first find the mass of the solution. The mass of the salt is given as 200 g, and we have 20 L of water. Since the total volume doesn't change when salt is added, we can assume the volume of the solution is still 20 L.
To find the mass of the solution, we add the mass of the salt and the mass of the water:
Mass of solution = Mass of salt + Mass of water
Mass of solution = 200 g + mass of water
Now, we need to find the mass of the water. We know that the density of water is 1 g/mL or 1 g/cm³. Since we have 20 L of water, we can convert it to grams using the density of water:
Mass of water = volume of water x density of water
Mass of water = 20 L x 1000 g/L
Mass of water = 20,000 g
Now, we can substitute the mass of water into the equation to find the mass of the solution:
Mass of solution = 200 g + 20,000 g
Mass of solution = 20,200 g
Next, we need to find the volume of the solution. We already know that it is 20 L.
Finally, we can calculate the density of the solution using the formula:
Density = Mass / Volume
Density = 20,200 g / 20 L
To have consistent units, it's better to convert the volume to cubic centimeters (cm³):
Density = 20,200 g / 20,000 cm³
Now, we can simplify and calculate the density:
Density = 1.01 g/cm³
Therefore, the density of the solution of salty water is 1.01 g/cm³.