A cash register contains only five dollar and ten dollar bills. It contains 25 more five dollar bills than ten dollar bills, and the total amount of money in the cash register is $560. How many of each bill is in the cash register?

F-25=T

5*F+10*T=560

5F+10*(F-25)=560
15F=560+250
F=810/15=54
T=29

To solve this problem, we can use a system of equations.

Let's assume the number of ten dollar bills is x.
Since there are 25 more five dollar bills than ten dollar bills, the number of five dollar bills would be (x + 25).

Now, we can set up two equations:

Equation 1: 10x + 5(x + 25) = 560 (to represent the total amount of money in the cash register)

Equation 2: (x + 25) = x + 25 (to represent the relationship between the number of five dollar bills and ten dollar bills)

Now, let's solve the equations to find the values of x and (x + 25):

Expanding Equation 1:
10x + 5x + 125 = 560

Combining like terms:
15x + 125 = 560

Subtracting 125 from both sides of the equation:
15x = 435

Dividing both sides by 15:
x = 29

Substituting the value of x back into Equation 2:
(x + 25) = 29 + 25
(x + 25) = 54

Therefore, there are 29 ten dollar bills and 54 five dollar bills in the cash register.