How many grams of a solid mixture containing strontium chloride would one need to make 558 mL of a 0.100 M strontium chloride solution, if the solid mixture contains 58.6% strontium chloride by weight

6.62 g

To calculate the grams of strontium chloride needed to make the desired solution, you need to follow these steps:

1. Determine the moles of strontium chloride needed.
2. Convert the moles of strontium chloride to grams.

Step 1: Determine the moles of strontium chloride needed.
The molarity (M) of a solution is defined as moles of solute per liter of solution. Therefore, to calculate the moles of strontium chloride needed, you can use the following equation:

mol = M × V

where:
- mol is the moles of strontium chloride
- M is the molarity of the strontium chloride solution
- V is the volume of the solution in liters

In this case, the molarity (M) is given as 0.100 M, and the volume (V) is given as 558 mL. However, it is convenient to convert the volume to liters by dividing it by 1000:

V = 558 mL ÷ 1000 = 0.558 L

Now, you can calculate the moles of strontium chloride:

mol = 0.100 M × 0.558 L = 0.0558 mol

Step 2: Convert the moles of strontium chloride to grams.
To convert the moles of strontium chloride to grams, you need to multiply the moles by the molar mass of strontium chloride. The formula for strontium chloride is SrCl2, and its molar mass can be obtained from the periodic table.

The molar mass of strontium (Sr) is approximately 87.62 g/mol, and the molar mass of chlorine (Cl) is approximately 35.45 g/mol. Since there are two chlorine atoms in strontium chloride, you need to multiply the molar mass of chlorine by 2.

Molar mass of strontium chloride (SrCl2) = (molar mass of strontium) + (molar mass of chlorine × 2)

Molar mass of strontium chloride (SrCl2) = 87.62 g/mol + (35.45 g/mol × 2) = 158.52 g/mol

Now, you can calculate the grams of strontium chloride needed:

grams = mol × molar mass

grams = 0.0558 mol × 158.52 g/mol = 8.83 g

Therefore, you would need approximately 8.83 grams of the solid mixture containing strontium chloride to make 558 mL of a 0.100 M strontium chloride solution, assuming the solid mixture contains 58.6% strontium chloride by weight.

How many mols do you need? That's M x L = mols. 0l00 x 0.558 L = ?

Then grams = mols x molar mass = ?
That's grams you need if the SrCl2 is 100%. It isn't so you need ?g from above/0.586 = ??

8.85 g