Calculate the ionization energy (in kj) for a mole of hydrogen atoms, making the assumption that ionization is the transition from n=1
the correct answer is : 1.31x10^3 kJ
See your other question above.
To calculate the ionization energy of hydrogen atoms, we need to use the equation:
Ionization Energy = (2.18 × 10^-18 J) × (Z^2 / n^2)
Where:
- 2.18 × 10^-18 J is the Rydberg constant
- Z is the atomic number or charge of the nucleus
- n is the principal quantum number representing the energy level or shell
In the case of hydrogen, Z = 1 since it only has one proton in its nucleus. The question specifies that the ionization transition is from n = 1. Plugging these values into the equation, we get:
Ionization Energy = (2.18 × 10^-18 J) × (1^2 / 1^2)
= (2.18 × 10^-18 J) × 1
= 2.18 × 10^-18 J
Since the answer is expected in kilojoules (kJ), we need to convert Joules to kilojoules by dividing by 1000:
Ionization Energy = 2.18 × 10^-18 J / 1000
= 2.18 × 10^-21 kJ
Therefore, the ionization energy for a mole of hydrogen atoms is:
Ionization Energy = (2.18 × 10^-21 kJ) × (6.022 × 10^23 atoms/mol)
≈ 1.31 × 10^3 kJ
Hence, the correct answer is 1.31 × 10^3 kJ.