A garment company makes two types of woolen sweaters and can produce a max of 700 sweaters per week. Each sweater of the first type requires 2 pounds of green wool and 4 pounds of pink wool to produce a single sweater. The second type of sweater requires 4 pounds of green wool and 3 pounds of pink wool. The profit earned the first type of sweater is $5 and on the second type $7 . The company has 50 ounds of green wool and 80 pound of pink wool.
Write a system of inequalities to represent the number of sweaters of the first type and the number of sweaters of the second type that can be produced.
let the number of sweaters of the first type be x
let the number of sweaters of the second type by y
x+y ≤ 700 ---- total sweaters
2x + 4y ≤ 50 --- green wook
4x + 3y ≤ 80 --- pink wool
Profit = 5x + 7y
A) what is the balance after one year if the interest is simple interest?
That depends upon the interest rate. Balance of what? How much is borrowed?
Did you ask the original question, or are you just causing a disruption?
Let's represent the number of sweaters of the first type as x and the number of sweaters of the second type as y.
Based on the given information, we can write the following inequalities:
1) The maximum number of sweaters that can be produced per week is 700:
x + y ≤ 700
2) Each sweater of the first type requires 2 pounds of green wool and 4 pounds of pink wool:
2x ≤ 50 (green wool constraint)
4x ≤ 80 (pink wool constraint)
3) Each sweater of the second type requires 4 pounds of green wool and 3 pounds of pink wool:
4y ≤ 50 (green wool constraint)
3y ≤ 80 (pink wool constraint)
4) The profit earned from the first type of sweater is $5 and from the second type is $7:
Profit from first type of sweater (x) = 5x
Profit from second type of sweater (y) = 7y
Therefore, the system of inequalities can be written as:
x + y ≤ 700
2x ≤ 50
4x ≤ 80
4y ≤ 50
3y ≤ 80