What is x for the following questions?
-2x-6=-12
3x+7=-15
-2x-6=-12
add 6 to both sides:
-2x = -6
divide by -2:
x = 3
or,
-2x-6=-12
add 2x to both sides:
-6 = -12+2x
add 12:
6 = 2x
divide by 2:
3 = x
or,
-2x-6=-12
divide by 2:
-x-3 = -6
...
Follow the same logic for the other one and see what you get.
I just noticed it was positive 12 haha but thank you!
Graph both lines and find the point where they intersect
To find the value of x in each equation, we can use algebraic methods. The goal is to isolate the variable x by performing the same arithmetic operations on both sides of the equation until x is alone on one side.
Let's solve each equation step by step:
Equation 1: -2x - 6 = -12
Step 1: Add 6 to both sides of the equation to get rid of the -6 on the left side:
-2x - 6 + 6 = -12 + 6
-2x = -6
Step 2: Divide both sides of the equation by -2 to isolate x:
(-2x) / -2 = -6 / -2
x = 3
So, the value of x in the first equation is 3.
Now let's move on to the second equation:
Equation 2: 3x + 7 = -15
Step 1: Subtract 7 from both sides of the equation to eliminate the +7 on the left side:
3x + 7 - 7 = -15 - 7
3x = -22
Step 2: Divide both sides of the equation by 3 to isolate x:
(3x) / 3 = -22 / 3
x = -22/3
Therefore, the value of x in the second equation is -22/3.