a body is released from the top of the tower Hmetres high. It takes t seconds to reach the ground .where is the body t/2 second after release
After t/2 seconds it has travelled a quarter of the total distance.
ht=12g.t2
Where ht is the total height and g is the acceleration due to gravity.
After t2 seconds :
ht2=12g(t2)2
=g(t2)8
So ht=4ht12
So you can see that after half the time it has travelled a quarter of the distance.
I hope this helps