A 5.00g of sodium chloride is Dissolved m, exactly 250 mL calibrated volumetric flask, what is the molarity of the solution?
How many mols are in 5.00 g NaCl? That's mols = grams/molar mass = ?
Then M = mols/L solution. 250 mL = 0.250 L.
To calculate the molarity of a solution, we need to know the amount of solute (in moles) and the volume of the solution (in liters).
In this case, we have 5.00 grams of sodium chloride (NaCl) and a total volume of 250 mL (0.250 L).
To find the number of moles of sodium chloride, we need to know its molar mass. The molar mass of NaCl is approximately 58.44 g/mol (sodium: 22.99 g/mol, chlorine: 35.45 g/mol).
To calculate the number of moles (n) of NaCl, we will use the formula:
n = mass ÷ molar mass
Plugging in the values, we have:
n = 5.00 g ÷ 58.44 g/mol
n ≈ 0.0856 mol
Now, let's calculate the molarity (M) of the solution using the formula:
M = moles of solute ÷ volume of solution
M = 0.0856 mol ÷ 0.250 L
M ≈ 0.342 M
Therefore, the molarity of the solution is approximately 0.342 M.