calculate the amount of nitrogen required for making 70g of ammonia
molesNH3=70/(14+3)
massN2= 28*molesN2=28*1/2*70/17
Remember Nitrogen is N2
Calculate mass and volume of ammonia produced when 70grams of nitrogen combines with hydrogen
To calculate the amount of nitrogen required to make 70g of ammonia, we first need to understand the molecular composition of ammonia.
Ammonia (NH3) consists of one atom of nitrogen (N) and three atoms of hydrogen (H). The relative atomic masses of nitrogen and hydrogen are 14 and 1 respectively.
To determine the amount of nitrogen required, we can use the molar mass of ammonia.
The molar mass of ammonia (NH3) = 1 x molar mass of nitrogen (N) + 3 x molar mass of hydrogen (H)
Molar mass of nitrogen (N) = 14 g/mol
Molar mass of hydrogen (H) = 1 g/mol
Molar mass of ammonia (NH3) = 1 x 14 + 3 x 1
= 17 g/mol
Now, we can calculate the amount of nitrogen required using the molar mass and given mass of ammonia.
Amount of nitrogen required = (Mass of ammonia / Molar mass of ammonia) x Molar mass of nitrogen
Substituting the values:
Amount of nitrogen required = (70 g / 17 g/mol) x 14 g/mol
Calculating this expression gives us the amount of nitrogen required to make 70g of ammonia.