use the remainder theorem to find the remainder when P(x) = x^4-9x^3-5x^2-3x+4 is divided by x + 3
please help me start this problem I have no idea
did you actually read the Remainder Theorem?
It says that the remainder when P(x) is divided by (x-a) is P(a). So, you want to just plug in -3 for x.
P(-3) = (-3)^4-9(-3)^3-5(-3)^2-3(-3)+4
= 81+243-45+9+4
...
Thank you
To use the remainder theorem to find the remainder when dividing the polynomial P(x) by x + 3, follow these steps:
Step 1: Set up the equation using the remainder theorem.
The remainder theorem states that if a polynomial P(x) is divided by x - a, the remainder is equal to P(a). In this case, a = -3 (since we are dividing by x + 3). So, we need to find P(-3).
Step 2: Substitute x = -3 into the polynomial P(x).
Replace every instance of x in the polynomial P(x) with -3 and simplify:
P(-3) = (-3)^4 - 9(-3)^3 - 5(-3)^2 - 3(-3) + 4
Step 3: Simplify the expression to find the remainder.
Calculate the value of P(-3):
P(-3) = 81 - 9(-27) - 5(9) + 9 + 4
Now, simplify this expression to find the remainder.