When a mass is hung from a spring stretches it by 15 cm. What is the period of the oscillations of this system?
k = m g/.15
omega = 2 pi/T = sqrt (k/m)
2 pi/T = sqrt (9.81/.15)
To find the period of oscillation for a mass-spring system, we need to use Hooke's Law and the formula for the period of a mass-spring system.
Hooke's Law states that the force applied by a spring is directly proportional to the displacement of the spring from its equilibrium position. Mathematically, it can be expressed as F = -kx, where F is the force, k is the spring constant, and x is the displacement.
In this case, when the mass is hung from the spring, it stretches by 15 cm (0.15 m). This displacement can be considered as the amplitude of the oscillations.
To find the period of oscillation, we need to use the formula T = 2π√(m/k), where T is the period, m is the mass, and k is the spring constant.
Since the mass is not given, we'll need more information to find the period.