The electric field from an infinitely large and uniformly charged sheet is independent of the distance from the sheet, yet the individual charges in the sheet all produce fields that object the inverse square law. Why doesn't the field get weaker at greater distances?

Are you calculus based?

If so, you know the field contributions in the direction perpendicular to the plane increases as the angle from far charges increases (due to the angle), that increases as the field from the close particles decreases.

The electric field from an infinitely large and uniformly charged sheet is independent of the distance from the sheet due to the cancellation of electric fields from individual charges in the sheet.

To understand this, imagine the sheet as being made up of an infinite number of charges distributed uniformly. Each individual charge on the sheet produces an electric field that follows the inverse square law. According to the inverse square law, the magnitude of the electric field decreases with the square of the distance from the charge.

However, when we consider the entire infinite sheet, we have contributions from all the charges. Near the sheet, charges that are closer to the point of interest exert a stronger electric field, while charges that are farther away contribute less to the overall field. Nevertheless, as we move farther away from the sheet, the closer charges that were responsible for the strong electric field are now being balanced by an increasing number of farther charges that were once less influential.

Due to the careful arrangement of charges within the sheet, the electric fields from individual charges cancel each other out as we move away from the sheet. The net result is that the contributions from the closer and farther charges balance each other perfectly, resulting in a uniform electric field that does not diminish with distance.

In essence, the cancellation effect ensures that the contributions from all charges on the sheet add up coherently and produce a constant electric field irrespective of the distance.