Find a polynomial with integer coefficients that satisfies the given conditions.

R has degree 4 and zeros 3 − 4i and 5, with 5 a zero of multiplicity 2.

x = 3 - 4i

x = 3 + 4i
x = 5
x =5

two 5's because multiplicity 2
You always have to have the conjugate of an imaginary number.

(x -(3-4i))(x-(3+4i)(x-5)(x-5) = 0
Easiest way is to multiply the first two and the second two factors.

Then multiply those answers together to get the polynomial.

(x-5)(x-5)(x-3+4i)(x-3-4i) = 0

(x^2-10x+25)(x^2-6x+25)

multiply that out

complex values come in pairs (why?), so the roots are

3-4i, 3+4i, 5, 5

R(x) = (x-(3-4i))(x-(3+4i))(x-5)^2
= ((x-3)+4i)((x-3)-4i)(x-5)^2
= ((x-3)^2+4^2)(x-5)^2
= (x^2-6x+25)(x-5)^2
= x^4 - 16x^3 + 110x^2 - 400x + 625

Find a polynomial with integer coefficients that satisfies the given conditions.

R has degree 4 and zeros 1 − 3i and 2, with 2 a zero of multiplicity 2.
R(x) =

3-4i, 3+4i, 2, 2

Find a polynomial with integer coefficients that satisfies the given conditions.

R has degree 4 and zeros 2 − 4i and 5, with 5 a zero of multiplicity 2.
R(x) =

To find a polynomial that satisfies the given conditions, we can start by using the fact that if a complex number is a zero of a polynomial with integer coefficients, then its conjugate must also be a zero.

Given that 3 - 4i is a zero, we know that its conjugate, 3 + 4i, must also be a zero. We also know that 5 is a zero of multiplicity 2, meaning it is a repeated zero.

To find the polynomial, we can start by setting up the factors:

(x - (3 - 4i))(x - (3 + 4i))(x - 5)(x - 5) = 0

Simplifying this, we get:

((x - 3) + 4i)((x - 3) - 4i)(x - 5)^2 = 0

Expanding the first two factors, we get:

((x - 3)^2 - (4i)^2)(x - 5)^2 = 0

Simplifying further, we get:

((x - 3)^2 - 16i^2)(x - 5)^2 = 0

Since i^2 = -1, we can simplify the polynomial to:

((x - 3)^2 + 16)(x - 5)^2 = 0

Expanding the terms, we get:

(x^2 - 6x + 9 + 16)(x - 5)^2 = 0

Simplifying further, we get:

(x^2 - 6x + 25)(x - 5)^2 = 0

Multiplying everything out, we get:

(x^4 - 16x^3 + 101x^2 - 300x + 625) = 0

Therefore, the polynomial with integer coefficients that satisfies the given conditions is:

f(x) = x^4 - 16x^3 + 101x^2 - 300x + 625