What volume of a 4.50 M KI stock solution would you use to make 0.455 L of a 1.25 M KI solution?

126

I obtained 0.126 L.

To find out the volume of the 4.50 M KI stock solution needed to make the 0.455 L of a 1.25 M KI solution, we can use the formula:

M1V1 = M2V2

Where:
M1 = initial molarity of the stock solution (4.50 M)
V1 = volume of the stock solution used (unknown)
M2 = final molarity of the desired solution (1.25 M)
V2 = final volume of the desired solution (0.455 L)

Rearranging the formula to solve for V1:

V1 = (M2 * V2) / M1

Plugging in the given values:

V1 = (1.25 M * 0.455 L) / 4.50 M

V1 = 0.126875 L

Therefore, you would need to use approximately 0.127 L (or 127 mL) of the 4.50 M KI stock solution to make 0.455 L of a 1.25 M KI solution.