Neil has a total of twelve $5 and $10 bills in his wallet. He has 5 times as many $10 bills as $5 dollar bills. How many of each does he have?
Let x = $5 bills
5x = $10 bills
x + 5x = 12
6x = 12
x = 2
y=x-6
y=2x
Let's solve this problem step by step:
Let's suppose Neil has x $5 bills.
According to the given conditions, Neil has 5 times as many $10 bills as $5 bills. Hence, he has 5x $10 bills.
The total number of $5 bills and $10 bills is given as twelve:
So, the equation becomes x + 5x = 12.
Simplifying the equation, we get:
6x = 12.
Dividing both sides of the equation by 6, we can find the value of x:
6x/6 = 12/6,
x = 2.
Therefore, Neil has 2 $5 bills and 5(2) = 10 $10 bills.
Neil has 2 $5 bills and 10 $10 bills.
To solve this problem, we can set up a system of equations.
Let x represent the number of $5 bills Neil has.
Let y represent the number of $10 bills Neil has.
We are given two pieces of information:
1) Neil has a total of twelve $5 and $10 bills in his wallet. This can be expressed as:
x + y = 12
2) Neil has 5 times as many $10 bills as $5 bills. This can be expressed as:
y = 5x
Now we can solve the system of equations.
Substituting the value of y from equation 2 into equation 1, we get:
x + 5x = 12
6x = 12
x = 2
Substituting the value of x into equation 2, we get:
y = 5(2)
y = 10
Therefore, Neil has 2 $5 bills and 10 $10 bills.