What volume of a 3.90 M KI stock solution would you use to make 0.430 L of a 1.25 M KI solution?
.43 L (1.25 mol/L) = .525 mols needed
.525 mols (1 Liter/3.9 mol)
= 0.135 Liters
To solve this question, you need to use the formula for dilution:
C1V1 = C2V2
Where:
C1 = initial concentration of the stock solution
V1 = volume of the stock solution used
C2 = final concentration of the diluted solution
V2 = final volume of the diluted solution
In this case:
C1 = 3.90 M
V1 = ?
C2 = 1.25 M
V2 = 0.430 L
Rearranging the formula, we have:
V1 = (C2 * V2) / C1
Substituting the given values, we can calculate:
V1 = (1.25 M * 0.430 L) / 3.90 M
= 0.137 L
Therefore, you would need to use 0.137 L (or 137 mL) of the 3.90 M KI stock solution to make 0.430 L of a 1.25 M KI solution.