How many grams of CaCl2 would be dissolved in 1.1 L of a 0.17 M solution of CaCl2?
.17 *1.1 = .187 mols
CaCl2 = 111 grams/mol
(40 + 2*35.5 )
.187 mol (111 g/mol) = 20.8 grams
i got this one wrong
To calculate the grams of CaCl2 dissolved in 1.1 L of a 0.17 M solution of CaCl2, you will need to use the formula:
moles = concentration (M) x volume (L)
First, convert the volume of the solution to liters:
1.1 L = 1.1 L
Next, substitute the values into the formula to calculate the moles of CaCl2:
moles = 0.17 M x 1.1 L
Multiply the concentration by the volume to get the moles:
moles = 0.187 mol
Finally, to convert moles to grams, you need to use the molar mass of CaCl2. The molar mass of CaCl2 is 110.98 g/mol.
grams = moles x molar mass
grams = 0.187 mol x 110.98 g/mol
grams = 20.74 g
Therefore, there would be approximately 20.74 grams of CaCl2 dissolved in 1.1 L of a 0.17 M solution of CaCl2.
To calculate the number of grams of CaCl2 that would be dissolved in the given solution, we need to use the formula:
moles = (concentration in M) * (volume in L)
First, let's calculate the number of moles of CaCl2 in 1.1 L of the solution:
moles = 0.17 M * 1.1 L = 0.187 moles
Now, we need to convert moles to grams using the molar mass of CaCl2. The molar mass of CaCl2 is 40.08 g/mol (calcium has a molar mass of 40.08 g/mol, and chlorine has a molar mass of 35.45 g/mol):
mass = moles * molar mass
mass = 0.187 moles * 110.98 g/mol (2 calcium atoms, 2 chlorine atoms)
mass = 20.809 g
Therefore, approximately 20.809 grams of CaCl2 would be dissolved in 1.1 L of a 0.17 M solution of CaCl2.