In an experiment on the shuttle, an electron with a speed of 6.3 x 105 m/s [N] and a mass of 9.11 x 10-31 kg is shot through an external magnetic field. Determine the strength and orientation of the magnetic field required so that the electron's direction of travel remains unchanged. Neglect any effects due to the Earth's magnetic field.

The magnetic field if aligned to the same direction as electron velocity, no force is on the electron, regardless of strength.

To determine the strength and orientation of the magnetic field that will keep the electron's direction of travel unchanged, we can apply the principle of the Lorentz force. The Lorentz force states that the force experienced by a charged particle moving through a magnetic field is given by the equation:

F = qvB sin(theta)

Where:
- F is the force experienced by the particle
- q is the charge of the particle
- v is the velocity of the particle
- B is the magnetic field strength
- theta is the angle between the velocity vector and the magnetic field vector

In this case, we want the electron's direction of travel to remain unchanged, which means the net force acting on it should be zero. Therefore, we can set the Lorentz force equal to zero:

F = qvB sin(theta) = 0

Since the electron is negatively charged, q = -e, where e is the elementary charge (-1.6 x 10^(-19) C).

Now we can rearrange the equation to solve for the magnetic field strength:

B sin(theta) = 0

Since sin(theta) ≠ 0, for the force to be zero, B must be equal to zero. This means that there is no requirement for a magnetic field if we want the electron's direction of travel to remain unchanged.

Therefore, the strength of the magnetic field required is zero, and the orientation of the non-existent field is not relevant for this scenario.