Physics

A cube weight 15N in air and 20N when totally immersed in water. Find the value of the cube of the density.

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asked by KAUNA
  1. Please proof read what you wrote. It has got to be backwards.

    the density of the cube I suppose :)

    displaces water weighing 5 Newtons

    5 N = 1000 kg/m^3 * 9.81 * Volume
    so
    Volume = 5.1* 10^-4 m^3

    mass = 20 N in air I think/9.81
    = 2.04 kg
    so

    rho = 2.04 kg/5.81*10^-4 m^3

    = 3.51 * 10^3 kg/m^3
    or 3.51 times density of water
    (rock?)

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    posted by Damon
  2. rho = 2.04 kg/5.1*10^-4 m^3

    = 4 * 10^3 kg/m^3

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    posted by Damon

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