A car of mass 1000kg starting from rest and comes down an incline slope if it travel 300m in 30 second calculate i) acceleration ii) force
d = (1/2) a t^2
300 = (1/2) a (900)
so
a = 600/900 = 2/3 = 0.67 m/s^2
F = m a = 670 N
To calculate the acceleration and force, we need to use Newton's second law of motion, which states that force (F) is equal to mass (m) multiplied by acceleration (a): F = m * a.
Here's how you can calculate the acceleration and force:
Step 1: Calculate the acceleration (a):
First, we need to find the final velocity (v) of the car after 30 seconds. We know that it started from rest, so the final velocity will be the distance traveled divided by the time taken: v = 300m / 30s = 10 m/s.
Now, we can use the formula for acceleration, which is the change in velocity (Δv) divided by the time taken (t):
a = Δv / t = (v - u) / t
Since the car started from rest, the initial velocity (u) is 0.
a = (10 m/s - 0 m/s) / 30 s = 10 m/s / 30 s = 1/3 m/s².
Therefore, the acceleration (a) is 1/3 m/s².
Step 2: Calculate the force (F):
We can now use Newton's second law of motion to calculate the force:
F = m * a
where m is the mass of the car.
Given that the mass (m) of the car is 1000 kg:
F = 1000 kg * (1/3 m/s²) = 1000/3 = 333.33 N.
Therefore, the force (F) acting on the car is 333.33 N.
To summarize:
i) The acceleration (a) is 1/3 m/s².
ii) The force (F) acting on the car is 333.33 N.