Physics - drwls?

A 2000 kg truck traveling north at 38 km/hr turns east and accelerates to 55 km/hr. What is the change in the truck's kinetic energy? What is the magnitude of the change in the linear momentum of the truck? What is the direction of the change in linear momentum of the truck? (give an angle, measured from east)

Convert the speeds to m/s and use (1/2) MV^2 for the kinetic energy. Momentum is MV, but is a vector so you must account for direction changes when calculating momentum change.

You need to learn the basic concepts and try applying them yourself. We will be happy to check your work.

I'm trying to do a similar problem for: 'What is the magnitude of the change in the linear momentum of the truck?'

Can you calculate it by just subtracting the initial momentum from the final momentum? ie
Change in momentum =
M x V(final) - M x V(initial)
Using this approach I can't get the right answer but I don't know any other way to do it.

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  1. by 110,000-76000 we get the answer 34000

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    posted by vibhor

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