Trimix 10/50 is a gas mixture that contains 10% oxygen and 50% helium, ant the rest is nitrogen. If a tank of Trimix 10/50 has a total pressure of 2.07 x 10 4 kPa, then what is the partial pressure of helium?
I presume the % is by volume; therefore, mole fraction He is 0.5
pHe = XHe*Ptotal
SHe = 0.5
Ptotal is given.
Solve for for pHe.
To determine the partial pressure of helium in the Trimix 10/50 gas mixture, we need to first calculate the percentage of helium in the tank and then use that percentage to calculate the partial pressure.
Given:
Total pressure (P) = 2.07 x 10^4 kPa
Oxygen percentage = 10%
Helium percentage = 50%
Step 1: Calculate the partial pressure of helium.
To calculate the partial pressure of helium, we can use the following formula:
Partial pressure of helium = Helium percentage * Total pressure
Partial pressure of helium = 50% * (2.07 x 10^4 kPa).
Step 2: Convert the percentage to a decimal.
To calculate the partial pressure of helium, we need to convert the percentage to a decimal by dividing it by 100:
Partial pressure of helium = 0.50 * (2.07 x 10^4 kPa).
Step 3: Perform the calculation to find the partial pressure of helium.
Partial pressure of helium = 0.50 * (2.07 x 10^4 kPa) = 1.035 x 10^4 kPa.
Therefore, the partial pressure of helium in the Trimix 10/50 gas mixture is 1.035 x 10^4 kPa.
To find the partial pressure of helium in the Trimix 10/50 gas mixture, we need to calculate it using the percentage composition and the total pressure of the mixture.
Step 1: Convert the total pressure from kPa to atm.
1 atm = 101.325 kPa
So, the total pressure is (2.07 x 10^4) / 101.325 = 204.01 atm.
Step 2: Calculate the partial pressure of helium.
Since the mixture contains 50% helium, we can calculate its partial pressure.
Partial pressure of helium = (50/100) x 204.01 atm = 102.005 atm.
Therefore, the partial pressure of helium in the Trimix 10/50 gas mixture is approximately 102.005 atm.