How to write |y|-2=0 in standard form?
Why did the variable go to the circus?
Because it wanted to perform a balancing act!
To write |y| - 2 = 0 in standard form, you need to get rid of the absolute value. Remember, the absolute value of any number is always either positive or zero.
So, if |y| - 2 = 0, you can rewrite it as y - 2 = 0 or -(y) - 2 = 0.
Therefore, the equation |y| - 2 = 0 in standard form is either y - 2 = 0 or -y - 2 = 0.
To write the equation |y| - 2 = 0 in standard form, follow these steps:
Step 1: Start with the equation |y| - 2 = 0.
Step 2: Rewrite the absolute value expression as two separate equations, one positive and one negative: y - 2 = 0 and -(y) - 2 = 0.
Step 3: Simplify the second equation: -y - 2 = 0.
Step 4: Add y to both sides of the second equation: -y + y - 2 = y + 0.
Step 5: Simplify the equation: -2 = y.
Step 6: Rearrange the equation to the standard form: y = -2.
Therefore, the equation |y| - 2 = 0 in standard form is y = -2.
To write the equation |y| - 2 = 0 in standard form, you need to eliminate the absolute value notation. Here's how you can do it:
Step 1: Isolate the absolute value expression.
Add 2 to both sides of the equation:
|y| - 2 + 2 = 0 + 2
This simplifies to:
|y| = 2
Step 2: Write the equation without the absolute value notation using two separate equations:
Recall that the absolute value of a number can be written as a positive value or a negative value. So we break the equation into two cases:
Case 1: y is positive
When y is positive, |y| is equal to y. Therefore, we can write this case as:
y = 2
Case 2: y is negative
When y is negative, |y| is equal to -y. Therefore, we can write this case as:
-y = 2
Step 3: Combine the two cases into one equation in standard form.
To write the equation in standard form, we need to rearrange the second case to have positive y:
-y = 2
Multiply both sides of the equation by -1:
y = -2
Now we can rewrite the two cases in standard form as:
y = 2, y = -2
Therefore, the equation |y| - 2 = 0 in standard form is y = 2, y = -2.
looks pretty standard to me.
Perhaps you mean:
|y|-2=0
|y| = 2
y = 2 or y = -2