|3y+4|-|=0
Write in standard form
typo ?
No it's not a typo .Rewrite Absolute value equations in standard form |3y+4|-|=0
|3y+4| means absolute value of 3y+4
-| means nothing to me.
its a -1 before the 0
So, why not use a 1?
|3y+4|-1 = 0
|3y+4| = 1
3y+4 = 1
3y = -3
y = -1
3y+4 = -1
3y = -5
y = -5/3
blah
To write the equation |3y+4| = 0 in standard form, let's start by understanding what this equation means.
The absolute value of a number represents its distance from zero on a number line. In this case, the absolute value of the expression (3y + 4) is equal to zero. This means that (3y + 4) is zero units away from zero.
Now, let's consider the definition of absolute value. The absolute value of a number "x" is equal to x if x is positive or zero, and it is equal to the opposite of x if x is negative.
Therefore, in order for the absolute value of (3y + 4) to be equal to zero, we can conclude that (3y + 4) itself must be equal to zero. We can set up the equation as follows:
3y + 4 = 0
Now, to write this equation in standard form, we need to rearrange the terms so that all the variables are on one side and the constant term is on the other side.
Subtracting 4 from both sides of the equation:
3y = -4
Finally, dividing both sides of the equation by 3, we can solve for "y":
y = -4/3
So, the equation |3y+4| = 0 in standard form is 3y = -4.