what is the molarity of the following solution?

13.8g of potassium trioxocarbonate (IV) in 200cm^3 of solution

M = mols solute/L solution.

mols solute = grams/molar mass = ?
L solution = 0.2 L

To find the molarity of the solution, we need to know the number of moles of potassium trioxocarbonate (IV) and the volume of the solution in liters.

First, let's find the number of moles of potassium trioxocarbonate (IV):

1. Convert the given mass of potassium trioxocarbonate (IV) from grams to moles using the molar mass of the compound. The molar mass of potassium trioxocarbonate (IV) is:
Molar mass(K2CO3) = (2 * molar mass of K) + molar mass of C + (3 * molar mass of O)
= (2 * 39.1 g/mol) + 12.0 g/mol + (3 * 16.0 g/mol)
= 78.2 g/mol + 12.0 g/mol + 48.0 g/mol
= 138.2 g/mol

Moles of potassium trioxocarbonate (IV) = mass / molar mass
= 13.8 g / 138.2 g/mol
= 0.0999 mol

Now, let's find the volume of the solution in liters:

2. Convert the given volume from cubic centimeters (cm^3) to liters (L).
Volume = 200 cm^3 = 200 mL = 200 L / 1000
= 0.2 L

Finally, we can calculate the molarity (M) using the formula:

Molarity = moles of solute / volume of solution in liters

Molarity = 0.0999 mol / 0.2 L
= 0.4995 M

Therefore, the molarity of the solution is approximately 0.4995 M.

To find the molarity, we need to know the number of moles of the solute (potassium trioxocarbonate) and the volume of the solution in liters.

1. First, calculate the number of moles of potassium trioxocarbonate (IV). To do this, we'll use the formula: Moles = Mass / Molar mass.

The molar mass of potassium trioxocarbonate (IV) is:
K = 39.10 g/mol
C = 12.01 g/mol
O = 16.00 g/mol

The molecular formula of potassium trioxocarbonate (IV) is K2CO3. So, its molar mass is:
(2 * 39.10 g/mol) + 12.01 g/mol + (3 * 16.00 g/mol) = 138.21 g/mol

Moles = 13.8 g / 138.21 g/mol = 0.0999 mol (approximately 0.1 mol)

2. Next, convert the volume of the solution from cm^3 to liters. Since 1 L = 1000 cm^3, the volume in liters is 200 cm^3 / 1000 = 0.2 L.

3. Finally, divide the moles of potassium trioxocarbonate (IV) by the volume of the solution in liters to find the molarity:

Molarity (M) = Moles / Volume (in liters)
= 0.1 mol / 0.2 L
= 0.5 M

Therefore, the molarity of the solution is 0.5 M.