one of the ingredients in detergent making, lauryl alcohol is extracted from coconut oil. A 5.00 g of this substance is added to 100 g of benzene and the solution boils at 80.78° C. what is the molar mass of lauryl alcohol?
10.5g of potassium trioxonitrate(v) salt saturated 5g of solvent at 15°c. Calculate the solubility of potassium trioxonitrate(v) salt at that same temperature in:
a) g/100g of solvents.
b)moles/ dm^3posted by Isaac
Isaac, don't piggy back on another question. Post your own.
Note that the problem says "this substance" which leads me to believe you are adding coconut oil to the benzene. If that is the case, you can't determine the molar mass of lauryl alcohol this way. I will assume "this substance" means you are adding that many grams of lauryl which has been extracted FROM the coconut oil.
delta T = Kb*molality
delta T = 80.78-normal boiling point benzene.
Kb--look up the Kb for benzene
Solve the above delta T = Kb*m for m. Then
m = molality = mols/kg solvent.
You know kg solvent = 100 g or 0.1 kg. Usisng Kg solvent and m, solve for mols.
Then mols = grams/molar mass. You know grams and mols, solve for molar mass.