Find area of triangle. Sides=12cm,9.2cm and 7.2cm
use hero's formula
sum all the side
a+b+c/2=s
now evaluate
area=√[s(s-a)(s-b)(s-c)]
good luck
collins meant:
(a+b+c)/2 = s
To find the area of a triangle when you know the lengths of its three sides, you can use Heron's formula. Heron's formula is given by:
Area = square root of (s × (s - a) × (s - b) × (s - c))
where "a," "b," and "c" are the lengths of the sides of the triangle, and "s" is the semi-perimeter of the triangle, calculated by:
s = (a + b + c) / 2
Let's calculate the area of the triangle using the given side lengths of 12 cm, 9.2 cm, and 7.2 cm.
1. Calculate the semi-perimeter, "s":
s = (12 + 9.2 + 7.2) / 2
s = 14.2 cm
2. Calculate the area using Heron's formula:
Area = √(s × (s - a) × (s - b) × (s - c))
Area = √(14.2 × (14.2 - 12) × (14.2 - 9.2) × (14.2 - 7.2))
Area = √(14.2 × 2.2 × 5 × 7)
Area = √(220 × 35)
Area = √(7700)
Area ≈ 87.8 cm²
Therefore, the area of the triangle with side lengths of 12 cm, 9.2 cm, and 7.2 cm is approximately 87.8 cm².