Find the equation of the line that is the image set of the flattening,
f(x,y)=(3x-3y, x-y)
Remember that f(1,0)=(a,c) and f(0,1)=(b,d) so plug the values of x and y f(0,1) or f(1,0) into the function to find the values for a,c or b,d.
Once you have values for x' and y' under the function then you can plug these values into the equation of a line to find the gardient which will give you the equation of the line.
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well, if u = x-y
v(u) = u/3
To find the equation of the line that is the image set of the given function, f(x, y) = (3x - 3y, x - y), we need to consider the x and y coordinates separately.
Let's start with the x-coordinate. Based on the given function, the x-coordinate of any point in the image set is equal to (3x - 3y). To express this in terms of x, we can solve the equation for y and rewrite it as follows:
3x - 3y = x
-3y = -2x
y = (2/3)x
Therefore, the x-coordinate of any point on the line in the image set can be denoted as x, whereas the y-coordinate can be represented as (2/3)x.
Thus, the equation of the line that is the image set of the flattening function f(x, y) = (3x - 3y, x - y) is y = (2/3)x.