A contractor is building a rectangular walkway 3 1/3ft wide by 35ft long using square cement pavers. Each paver has an area if 4/9ft^2. What is the least number of pavers he needs to make the walkway?
Can someone explain?
Multiple 3 1/3 times 35
divide that answer by 4/9
I get 262.5 or 263
Typo? 4/9ft^2.
No its not a typo 4/9ft squared that's what my book says
that's what the "^2" is
This actually the reason it confused me... Do you know?
Sorry -- but I don't understand. Logically it would be (4',9")^2.
Also -- the pavers are probably concrete, not cement, blocks.
http://www.google.com/#q=cement
I think you are correct with (4',9")^2 but I don't know.
Thanks!
Answer should be on pg 858 in your book
To find the least number of pavers needed to make the walkway, we first need to calculate the area of the walkway.
The width of the walkway is given as 3 1/3 ft. We can convert this mixed fraction to an improper fraction by multiplying the whole number (3) by the denominator (3) and adding the numerator (1). This gives us (3 * 3 + 1 = 10). So the width of the walkway is 10/3 ft.
The length of the walkway is given as 35 ft.
To find the area of the walkway, we multiply the width by the length: (10/3) * 35 = (10 * 35) / 3 = 350/3 ft^2.
Now that we know the area of the walkway, we can calculate the number of pavers needed by dividing the area of the walkway by the area of each paver.
The area of each paver is given as 4/9 ft^2.
To find the number of pavers, we divide the area of the walkway by the area of each paver: (350/3) / (4/9) = (350/3) * (9/4) = (350 * 9) / (3 * 4) = 3150 / 12 = 262.5.
Since we cannot have half a paver, we need to round up to the nearest whole number. Therefore, the least number of pavers the contractor needs to make the walkway is 263.