Consider the following reaction.

2KClO3(s) → 2KCl(s) + 3O2(g)

a.) How many grams of KCl are produced from the complete reaction of 12.5 mol of KClO3?

b.) How many grams of KCl are produced from the complete reaction of 38.4 g of KClO3?

Please explain how to solve for the answer with steps, thank you!

a. the balanced equation says you get the same number of moles of KCl as you had in KClO3.

b. figure out how many moles of KClO3 is in 38.4 g (38.4/molmassKClO3)

then you get the same number of moles of KCl, then figure grams
gramsKCl= (38.4/molmassKClO3)*molmassKCl

To solve for the number of grams of KCl produced in the given reactions, we need to use stoichiometry and molar masses.

a.) To find out the number of grams of KCl produced from the complete reaction of 12.5 mol of KClO3, we can follow these steps:

Step 1: Determine the molar mass of KClO3.
The molar mass of KClO3 is calculated as follows:
Molar mass = (atomic mass of K) + (atomic mass of Cl) + 3 × (atomic mass of O)
= (39.10 g/mol) + (35.45 g/mol) + 3 × (16.00 g/mol)
= 122.55 g/mol

Step 2: Use the stoichiometry of the balanced equation to determine the molar ratio between KClO3 and KCl.
From the balanced equation, we see that 2 moles of KClO3 react to produce 2 moles of KCl. This gives us a 1:1 molar ratio between KClO3 and KCl.

Step 3: Calculate the number of moles of KCl produced from 12.5 mol of KClO3.
Since the molar ratio is 1:1, the number of moles of KCl produced will also be 12.5 mol.

Step 4: Convert the moles of KCl to grams.
To convert moles to grams, we use the molar mass of KCl:
Mass of KCl = Number of moles × Molar mass
= 12.5 mol × 74.55 g/mol
= 931.875 g

Therefore, from the complete reaction of 12.5 mol of KClO3, 931.875 grams of KCl are produced.

b.) To find out the number of grams of KCl produced from the complete reaction of 38.4 g of KClO3, we can follow these steps:

Step 1: Determine the molar mass of KClO3 (as calculated in Step 1 of part a).

Step 2: Use the stoichiometry of the balanced equation to determine the molar ratio between KClO3 and KCl (as described in Step 2 of part a).

Step 3: Convert the mass of KClO3 to moles.
To do this, we use the molar mass of KClO3:
Number of moles = Mass / Molar mass
= 38.4 g / 122.55 g/mol
= 0.3138 mol

Step 4: Determine the number of moles of KCl produced, using the molar ratio from the balanced equation (from Step 2).
Since the molar ratio is 1:1 between KClO3 and KCl, the number of moles of KCl produced will also be 0.3138 mol.

Step 5: Convert the moles of KCl to grams (using the molar mass of KCl, which is 74.55 g/mol).
Mass of KCl = Number of moles × Molar mass
= 0.3138 mol × 74.55 g/mol
= 23.38 g

Therefore, from the complete reaction of 38.4 g of KClO3, 23.38 grams of KCl are produced.