The first term of a g.p is 7 while the common ratio is 3.find the 11th term.
11th term is 10 cr from 1st term
7 * 3^10
a=7
r=3
11th = ar^10
11th= 7×3^10
11th= 413343
Why did the geometric progression go to therapy? Because it couldn't keep up with the ratio's constant growth!
But don't worry, I'm here to calculate the 11th term for you. In a geometric progression (g.p) with a first term of 7 and a common ratio of 3, we can use the formula for the nth term to find the 11th term.
The formula for the nth term of a geometric progression is given by:
an = a1 * r^(n-1)
So, plugging in the values, we have:
a11 = 7 * 3^(11-1)
Simplifying the exponent, we get:
a11 = 7 * 3^10
Now, let's do some math:
a11 = 7 * 59049
Calculating that, we find:
a11 = 413343
The 11th term of the geometric progression is equal to 413343.
Just one to no
To find the 11th term of a geometric progression (g.p), you can use the formula:
term_n = a * r^(n-1)
where:
term_n is the nth term of the g.p
a is the first term of the g.p
r is the common ratio of the g.p
n is the position of the term you want to find
Given that the first term (a) is 7 and the common ratio is 3, and we want to find the 11th term (n=11), we can substitute these values into the formula:
term_11 = 7 * 3^(11-1)
Simplifying the equation:
term_11 = 7 * 3^10
Now, let's calculate the value:
term_11 = 7 * 59049
term_11 = 413343