There are at least 5 more than twice as many students taking algebra 1 than taking algebra 2. If there are 44 students taking algebra 2, what is the least number of students who could be taking algebra 1. Show all work
You need to try to do some of the work yourself and show your work. Then someone here may be able to help you.
What i would say is work backwards. So if there are 44 students in Algebra 2, and it states that there are twice as many in Alg.1 then 2. So, then there are twice that amount in Algebra 1. It also states that there are at least 5 more than that, so you add another 5 students. I would say your answer should be.. 93 students in Algebra 1 at the least.
I received the answer of 93 and it was incorrect, that is why i am asking for help
93
93+
To find the least number of students taking algebra 1, we need to determine the minimum number of students that satisfies the given condition.
Let's break down the problem step by step:
Step 1: Identify the known information.
We know that there are 44 students taking algebra 2.
Step 2: Set up the equation.
The problem states that there are at least 5 more than twice as many students taking algebra 1 than taking algebra 2. Mathematically, we can represent the number of students taking algebra 1 as (2x + 5), where x represents the number of students taking algebra 2.
Step 3: Substitute the known information into the equation.
In this case, we substitute x = 44 into (2x + 5) to find the minimum number of students taking algebra 1.
(2 * 44) + 5 = 88 + 5 = 93
Therefore, the least number of students that could be taking algebra 1 is 93.