a scuba diver breathing normal air descends 100m of depth, where the total pressure is 11 atm. What is the partial pressure of oxygen that the diver experiences at this depth?

Can someone help out on this question?

Make a ratio:

11atm/1atm= P/partial pressureO2 at surface

Solve for P

2.3 atm

To find the partial pressure of oxygen (O2) at a depth of 100m where the total pressure is 11 atm, we can set up a ratio:

11 atm / 1 atm = P / partial pressure of O2 at the surface

Here, P represents the partial pressure of oxygen at 100m depth. To solve for P, we can rearrange the equation to isolate P:

P = (11 atm / 1 atm) * partial pressure of O2 at the surface

The partial pressure of oxygen at the surface typically varies, but it is commonly around 0.21 atm. Substituting this value into the equation:

P = (11 atm / 1 atm) * 0.21 atm

P = 2.31 atm

Therefore, the partial pressure of oxygen that the scuba diver experiences at a depth of 100m is approximately 2.31 atm.

To find the partial pressure of oxygen that the scuba diver experiences at a depth of 100m, we can use Dalton's Law of Partial Pressures. Dalton's Law states that the total pressure exerted by a mixture of gases is equal to the sum of the partial pressures of each individual gas.

In this case, the total pressure at a depth of 100m is given as 11 atm. We want to find the partial pressure of oxygen (O2) at this depth.

The first step is to set up a ratio using Dalton's Law. The ratio will be the total pressure at the depth (11 atm) divided by the partial pressure of oxygen at the surface (which is 1 atm). So the ratio is:

11 atm / 1 atm = P / partial pressure of O2 at surface

Now, we can solve for P by cross-multiplying:

11 atm * partial pressure of O2 at surface = 1 atm * P

This simplifies to:

11 * partial pressure of O2 at surface = P

Finally, to find the partial pressure of oxygen at a depth of 100m, we need to know the partial pressure of oxygen at the surface. Typically, the partial pressure of oxygen in air at sea level is about 0.21 atm. So we can substitute this value and solve for P:

11 * 0.21 atm = P

P = 2.31 atm

Therefore, the partial pressure of oxygen that the scuba diver experiences at a depth of 100m is approximately 2.31 atm.