What is the period of mathematical pendulum with a lenght of 39,2 m ?
T=2π•sqrt(L/g)
To find the period of a mathematical pendulum, we can use the formula:
T = 2π * √(L/g)
where T is the period, L is the length of the pendulum, and g is the acceleration due to gravity.
Given the length of the pendulum as 39.2 m, and the approximate value of g as 9.8 m/s^2, we can plug these values into the formula to find the period:
T = 2π * √(39.2 / 9.8)
T = 2π * √(4)
T = 2π * 2
T = 4π seconds
Therefore, the period of the mathematical pendulum with a length of 39.2 m is 4π seconds.
To calculate the period of a mathematical pendulum, you need to use the equation:
T = 2π√(L/g)
Where T represents the period of the pendulum, L represents the length of the pendulum, and g represents the acceleration due to gravity.
In this case, the length of the pendulum (L) is given as 39.2 m. The standard value for the acceleration due to gravity (g) is approximately 9.8 m/s².
Plugging these values into the formula, we can calculate the period:
T = 2π√(39.2 / 9.8)
Now let's calculate the value.
T = 2π√(4)
T = 2π * 2
T = 4π
Therefore, the period of the mathematical pendulum with a length of 39.2 m is 4π seconds.