One zero of x^3 – 3x^2 – 6x + 8 = 0 is -2. What are the other zeros of the function?
divide by factor (x+2)
(x^3 – 3x^2 – 6x + 8)/(x+2)
= x^2-5x+4
which is
(x-4)(x-1)
so
4 and 1
(x^3 – 3x^2 – 6x + 8)/(x+2)
= x^2-5x+4
which is
(x-4)(x-1)
so
4 and 1