In 1994 school lunch was $1.20. In 1999 it increased to $2.25. FInd the rate of change for school lunch from 1994-1999
Divide 6 into 2.25. The rate went up about .375 cents a year.
By what you said in the problem, I think you are trying to find a percent. In this case, you could set up an eqaution. Do you know cross multiplication. Well, just in case you don't, I'll show you.
x/100 = 1.20/2.25
Then what you would do is multiply 1.20 by 100, then divide by 2.25.
And there's your answer!
Hope I helped!
ok thank you so much!!!
Another way to solve this problem:
2.25 - 1.20 = 1.05
1.05 / 1.2 = 0.875 = 87.5%
You're welcome. I'm glad I could help!
To find the rate of change for school lunch from 1994 to 1999, we need to calculate the difference in price and divide it by the number of years.
Rate of change = (Final Value - Initial Value) / Number of Years
In this case:
Initial Value = $1.20 (price in 1994)
Final Value = $2.25 (price in 1999)
Number of Years = 1999 - 1994 = 5 years
Plugging the values into the formula:
Rate of change = ($2.25 - $1.20) / 5
Calculating the difference:
Rate of change = $1.05 / 5
Simplifying the division:
Rate of change = $0.21 per year
Therefore, the rate of change for school lunch from 1994 to 1999 is $0.21 per year.