What is amount of ammonia produced from 56 gm of nitrogen gas
To calculate the amount of ammonia produced from a given mass of nitrogen gas, we need to use stoichiometry, which involves balancing the chemical equation and using the molar ratios.
First, let's write the balanced chemical equation for the reaction that produces ammonia from nitrogen gas:
N2 + 3H2 → 2NH3
From the equation, we can see that 1 mole of nitrogen gas (N2) reacts with 3 moles of hydrogen gas (H2) to produce 2 moles of ammonia (NH3).
Now, we need to convert the given mass of nitrogen gas (56 g) into moles. To do this, we use the molar mass of nitrogen, which is approximately 28 g/mol:
moles of N2 = mass of N2 / molar mass of N2
moles of N2 = 56 g / 28 g/mol
moles of N2 = 2 mol
Since the molar ratio between nitrogen gas and ammonia is 1:2, we can determine the moles of ammonia produced as follows:
moles of NH3 = moles of N2 × (2 moles of NH3 / 1 mole of N2)
moles of NH3 = 2 mol × (2 mol of NH3 / 1 mol of N2)
moles of NH3 = 4 mol
Finally, we can convert the moles of ammonia into grams by using the molar mass of ammonia, which is approximately 17 g/mol:
mass of NH3 = moles of NH3 × molar mass of NH3
mass of NH3 = 4 mol × 17 g/mol
mass of NH3 = 68 g
Therefore, the mass of ammonia produced from 56 g of nitrogen gas is 68 g.