In a bag there are 3 green apples,5 yellow apples,7 green pears and 2 yellow pears,Simon randomly is taking fruit out of the bag by one by one. How many fruits must he take out in order to be certain that he has at least one apple and one pear of the same color?
The answer will be 13 because he will have to be unlucky and take out all yellow apples and all green pears, then you need requirement add 1 and you get 13
13
To determine the minimum number of fruits Simon must take out to be certain that he has at least one apple and one pear of the same color, we can analyze the worst-case scenario.
The worst-case scenario would be if Simon picks only green apples first, followed by yellow pears. In this case, he would need to draw all the green apples (3) and all the yellow pears (2) before he can guarantee having one apple and one pear of the same color.
So, to answer the question, Simon must take out 3 green apples and 2 yellow pears, totaling 5 fruits, in order to be certain that he has at least one apple and one pear of the same color.
worst case
... he takes out 5 ya and 7 gp
the 13th fruit will fill the requirement