How many carbon dioxide molecules will form when a naptha molecule burns?
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Write the equation, then solve it just as we did the problem on water molecules yesterday. Post in detail any questions you have about what to do next.
To determine the number of carbon dioxide molecules formed when a naphtha molecule burns, we need to start by writing a balanced chemical equation for the combustion of naphtha.
The general formula for naphtha is CnH2n+2. However, since we are not given a specific value for 'n', we will assume a simple case where 'n' is equal to 6.
Therefore, naphtha can be represented by C6H14.
The combustion of naphtha is an exothermic reaction, and it can be represented by the following balanced chemical equation:
C6H14 + 19/2 O2 → 6 CO2 + 7 H2O
According to the balanced equation, for every one molecule of naphtha (C6H14), six molecules of carbon dioxide (CO2) are formed.
Therefore, the answer to the question is that six carbon dioxide molecules will form when one molecule of naphtha burns.
Remember that the numbers in balanced chemical equations represent the stoichiometric ratios between the different substances in the reaction, and can be used to determine the number of molecules formed or consumed during the reaction.
If the question asked for a different number of naphtha molecules or a different value of 'n', the answer would change accordingly.