1. Not sure of how to do the calculations...
Make a 0.200 m solution of NaCl in a 100. mL volumetric flask. ... Solution A's question or statement is the same but with M (molarity)
Is this right? The small m means molality. If it were changed to capital M, then solution A's MOLARITY is 1.17 g. Would both solutions be the same ?
0.1 L * (0.200 m NaCl/1L)*(58.443 g NaCl/1 mole NaCl) = 1.17 g NaCl
Would Sol'A contain more, less, or same moles of solute (NaCl)?
And finally, Is the volume of Sol A more, less, or the same as the volume of Sol'B? Why?
To determine the moles of solute (NaCl) in solution A, we can use the formula:
moles = molality * mass of solvent
First, let's calculate the moles of NaCl in solution A:
molality = 0.200 m NaCl (given)
mass of solvent = volume of solution A = 0.100 L (given that it is in a 100 mL volumetric flask)
Now, substitute the values into the formula:
moles of NaCl = 0.200 m NaCl * 0.100 L = 0.020 moles
To convert the moles to grams, we can use the molar mass of NaCl:
molar mass of NaCl = 58.443 g/mol
Now, let's calculate the mass of NaCl in solution A:
mass = moles * molar mass
mass of NaCl = 0.020 moles * 58.443 g/mol = 1.169 g
Therefore, the mass of solute (NaCl) in solution A is 1.169 g.
Now, let's move on to solution B. If solution A's concentration is expressed in molarity (M), then the calculations will differ. Molarity is defined as moles of solute per liter of solution.
The given molarity for solution A is 1.17 g. Assuming this is the molarity (M), let's calculate the moles of NaCl in solution A:
molarity = 1.17 M NaCl (given)
volume of solvent = 0.100 L (given)
Now, substitute the values into the formula:
moles of NaCl = molarity * volume = 1.17 mol/L * 0.100 L = 0.117 moles
Therefore, the moles of solute (NaCl) in solution A is 0.117 moles.
Comparing the moles of solute in solution A and B, we find that solution A has more moles of solute (NaCl) since 0.117 moles > 0.020 moles.
Now let's analyze the volume of solution A compared to the volume of solution B. Since the volume of solution B is not given, we cannot directly compare the volumes of the two solutions.
In summary:
- The mass of solute (NaCl) in solution A is 1.169 g.
- The moles of solute (NaCl) in solution A is 0.020 moles.
- The moles of solute (NaCl) in solution B is 0.117 moles.
- The volume of solution A and B cannot be compared without knowing the volume of solution B.