its takes 145 mL of zinc nitrate to react completely with 175 ml of 1.5 M potassium hydroxide. what is the concentration if zinc nitrate?
To find the concentration of zinc nitrate, we need to use the formula for calculating concentration:
Concentration (M) = moles / volume (L)
First, let's find the number of moles of potassium hydroxide (KOH) using its volume and concentration.
Given:
Volume of KOH (V1) = 175 mL = 175/1000 L = 0.175 L
Concentration of KOH (C1) = 1.5 M
Using the formula, we can find the moles of KOH:
Moles of KOH (n1) = Concentration (C1) * Volume (V1)
= 1.5 M * 0.175 L
= 0.2625 moles
Since the reaction between zinc nitrate (Zn(NO3)2) and potassium hydroxide (KOH) is 1:2, the moles of zinc nitrate will be twice the moles of KOH.
Moles of Zn(NO3)2 (n2) = 2 * Moles of KOH (n1)
= 2 * 0.2625 moles
= 0.525 moles
Now, let's calculate the volume of zinc nitrate using its moles and the given volume:
Given:
Moles of Zn(NO3)2 (n2) = 0.525 moles
Volume of Zn(NO3)2 (V2) = 145 mL = 145/1000 L = 0.145 L
Using the formula, we can find the concentration of zinc nitrate:
Concentration of Zn(NO3)2 (C2) = Moles of Zn(NO3)2 (n2) / Volume of Zn(NO3)2 (V2)
= 0.525 moles / 0.145 L
≈ 3.62 M
Therefore, the concentration of zinc nitrate (Zn(NO3)2) is approximately 3.62 M.