Dylan invested some money into his bank.

He agreed on a simple interest rate of 3% per annum for a period of 2 years.
At the end of the 2-year period, the value of his investment increased by£72

Work out the value of Dylan's initial investment.

two years at 3% = .03*2 = .06

so
.06 times original deposit = 72

so 72/.06
which is
1200

Sorry to be a pain, but I don't really understand this answer.

Could you explain to me?

Thank you very much!

Hi,

I could work, please can you answer the question.
Dylan inverted some money in his bank.
He agreed to a simple interest rate of 3% per annum for a period of 2 years.
At the end of the 2-year period, the value of his investment increased by £72.
Work out the value of Dylan’s initial investment.

1200

£1200

To work out the value of Dylan's initial investment, we need to use the formula for simple interest:

I = P * r * t

Where:
I = Interest
P = Principal (initial investment)
r = Interest rate per annum
t = Time period

Given:
r = 3% = 0.03 (converted to decimal form)
t = 2 years
I = £72

Substituting the values into the formula, we get:

£72 = P * 0.03 * 2

Simplifying the equation, we have:

£72 = P * 0.06

Dividing both sides of the equation by 0.06:

£72 / 0.06 = P

This gives us:

£1,200 = P

Therefore, the value of Dylan's initial investment was £1,200.

So is it 1200%?

Thank you i am a Year 7 and my head of maths set this as a challenge and i think it is GCSE questions.

I didn't quite understand it and the video never helped me.
Don't make fun because i am 11 years old doing stuff for mabye 16-17 year olds

.06 v = £72