The figure shows a jet engine suspended beneath the wing of an airplane. The weight of the engine is 12600 N and acts as shown in the figure. In flight the engine produces a thrust of 69100 N that is parallel to the ground. The rotational axis in the figure is perpendicular to the plane of the paper. With respect to this axis, find the magnitude of the torque due to (a) the weight and (b) the thrust.
Once again you have not given the moment arms
Torque or moment is force * distance from axis
To find the magnitude of the torque due to the weight and the thrust, we need to understand the concepts of torque and how it is calculated.
Torque, or the moment of force, is the rotational equivalent of force. It measures the tendency of a force to rotate an object about an axis. The magnitude of torque is given by the formula:
Torque = Force * Distance * sin(Θ)
where:
- Force is the applied force
- Distance is the perpendicular distance from the axis of rotation to the line of action of the force
- Θ is the angle between the applied force and the line connecting the axis of rotation and the point of application of the force.
Now, let's calculate the magnitude of the torque due to the weight and the thrust separately:
(a) Torque due to the weight:
The weight of the engine acts vertically downward, which means it makes an angle of 90 degrees with the line connecting the axis of rotation and the point of application. Therefore, sin(Θ) = 1.
Given that the weight of the engine is 12600 N, the distance is not specified in the question. We need to know the perpendicular distance from the axis of rotation to the line of action of the weight.
Once we have the distance, we can use the formula to calculate the torque:
Torque due to weight = Weight of engine * Distance * sin(Θ) = 12600 N * Distance * 1 = 12600 N * Distance
(b) Torque due to the thrust:
The thrust of the engine acts parallel to the ground, which means it makes an angle of 0 degrees with the line connecting the axis of rotation and the point of application. Therefore, sin(Θ) = 0.
Given that the thrust of the engine is 69100 N, the distance is not specified in the question. We need to know the perpendicular distance from the axis of rotation to the line of action of the thrust.
Once we have the distance, we can use the formula to calculate the torque:
Torque due to thrust = Thrust of engine * Distance * sin(Θ) = 69100 N * Distance * 0 = 0
Therefore, the magnitude of the torque due to the thrust is 0.
Keep in mind that the answer to both parts (a) and (b) of the question depends on the distance between the axis of rotation and the line of action of the forces. Without this information, we cannot determine the exact magnitudes of the torques.