Can you check please.
1. Melvin had 20 children in his
kindergarten class. Two-fifths of the
children had brown eyes. Onefourth
of the children had blue eyes.
The rest had hazel eyes. How many
children had hazel eyes?
20(2/5) = 8 brown
20(1/4) = 5 blue
8+5=13. So 21-13 = 7 hazel
Right.
Well geez you're pretty darn smart.I'm wondering what you're doing in the 4th grade.
20-17*
20-13*
To solve this problem, we will use the information given in the question. We know that Melvin had 20 children in his kindergarten class.
First, let's find out how many children had brown eyes. The question states that two-fifths (2/5) of the children had brown eyes. To calculate this, multiply 20 by 2/5:
20 * (2/5) = 8
So, 8 children had brown eyes.
Next, let's find out how many children had blue eyes. The question states that one-fourth (1/4) of the children had blue eyes. To calculate this, multiply 20 by 1/4:
20 * (1/4) = 5
Thus, 5 children had blue eyes.
Finally, we can determine the number of children with hazel eyes. Since we already know that there were a total of 20 children in the class, we can subtract the number of children with brown eyes and blue eyes from this total:
20 - 8 - 5 = 7
Therefore, there were 7 children with hazel eyes in Melvin's kindergarten class.